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-4y^2-y+4=0
We add all the numbers together, and all the variables
-4y^2-1y+4=0
a = -4; b = -1; c = +4;
Δ = b2-4ac
Δ = -12-4·(-4)·4
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{65}}{2*-4}=\frac{1-\sqrt{65}}{-8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{65}}{2*-4}=\frac{1+\sqrt{65}}{-8} $
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